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Question

Chemistry Question on The Valence Shell Electron Pair Repulsion (VSEPR) Theory

Number of lone pairs of electrons on Xe atoms in XeF2,XeF4XeF_2, XeF_4 and XeF6XeF_6 molecules are respectively

A

3, 2 and 1

B

4, 3 and 2

C

2, 3 and 1

D

3, 2 and 0

Answer

3, 2 and 1

Explanation

Solution

No. of electrons around Xe in XeF2 = 8 + 2 = 10 Electron pairs =10/2 = 5 Bond pairs = 2 Lone pairs = 5-2 = 3 Similarly, lone pairs in XeF4XeF_4 = 2 and lone pair in XeF6XeF_6 = 1