Question

Number of isomers possible for ${{C}_{4}}{{H}_{8}}O$ is:

• A. 3
• B. 4
• C. 5
• D. 6

Answer 1

Answer: (D)

6

Answer 2

There are $6$ isomers possible for the compounds having molecular formula $C _{4} H _{8} O$, which are as follows : $\underset{(i)}{CH_3CH_2\overset{\underset{||}{O}}{C} - CH_3}, \,\,\, \underset{(ii)}{CH_3CH_2CH_2CHO}$ and $\underset{(vi)}{CH_2 =CH - CH_2CH_2OH}$