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Chemistry Question on Hydrocarbons

Number of isomeric products formed by monochlorination of 2-methylbutane in presence of sunlight is _______.

Answer

In the monochlorination of 2-methylbutane, chlorine can replace a hydrogen atom at different positions, leading to the formation of structural and stereoisomeric products. The possible isomeric products are:

CH3−CH(Cl)−CH2−CH(CH3)−CH3 (±)\text{CH}_3 - \text{CH}(\text{Cl}) - \text{CH}_2 - \text{CH}(\text{CH}_3) - \text{CH}_3 \, (\pm) CH3−CH(CH3)−CH2−CH(Cl)−CH3\text{CH}_3 - \text{CH}(\text{CH}_3) - \text{CH}_2 - \text{CH}(\text{Cl}) - \text{CH}_3 CH3−C(Cl)(CH3)−CH2−CH3 (±)\text{CH}_3 - \text{C}(\text{Cl})(\text{CH}_3) - \text{CH}_2 - \text{CH}_3 \, (\pm)

Therefore, there are 6 isomeric products.