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Question: Number of gm of oxygen in 32.2 g \(Na_{2}SO_{4}.10H_{2}O\)is...

Number of gm of oxygen in 32.2 g Na2SO4.10H2ONa_{2}SO_{4}.10H_{2}Ois

A

20.8

B

22.4

C

2.24

D

2.08

Answer

22.4

Explanation

Solution

Na2SO46mu.6mu10H2ONa_{2}SO_{4}\mspace{6mu}.\mspace{6mu} 10H_{2}O =2×23+32+4×16+10×18= 2 \times 23 + 32 + 4 \times 16 + 10 \times 18

=46+32+64+180=322gm= 46 + 32 + 64 + 180 = 322gm

322gm Na2SO4.10H2ONa_{2}SO_{4}.10H_{2}O contains = 224 gm oxygen

32.2gm Na2SO4.10H2ONa_{2}SO_{4}.10H_{2}O contains

= 32.2×224322=22.4gm\frac{32.2 \times 224}{322} = 22.4gm