Question

number of electrons having l=0 is 10 in pd

Answer 1

The statement is false, the correct number is 8.

Answer 2

The number of electrons with azimuthal quantum number $l=0$ corresponds to the total number of electrons in all s-subshells ($1s, 2s, 3s, 4s, 5s, \dots$).

The electronic configuration of Palladium (Pd, Z=46) is $[Kr] 4d^{10}$. This means the configuration is $1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10} 4s^2 4p^6 4d^{10}$. The s-subshells present are $1s$, $2s$, $3s$, and $4s$, each containing 2 electrons. The $5s$ subshell is empty in the ground state.

Total s-electrons = electrons in $1s$ + electrons in $2s$ + electrons in $3s$ + electrons in $4s$ = 2 + 2 + 2 + 2 = 8.

The statement claims the number is 10, which is incorrect.