Question

Number of divisors of the form $(4n + 2), n\ge 0$ of the integer 240 is

• A. 4
• B. 8
• C. 10
• D. 3

Answer 1

Answer: (A)

4

Answer 2

Since, $240 = 2^4$.3.5

$\therefore$Total number of divisors $= (4 + 1)(2)(2) =20$
Out of these 2, 6, 10, and 30 are of the form 4n + 2.
Therefore, (a) is the answer.