Question
Chemistry Question on Chemical bonding and molecular structure
Number of complexes from the following with even number of unpaired "d" electrons is _____. [V(H2O)6]3+,[Cr(H2O)6]2+,[Fe(H2O)6]3+,[Ni(H2O)6]3+,[Cu(H2O)6]2+ [Given atomic numbers: V=23,Cr=24,Fe=26,Ni=28,Cu=29]
2
4
5
1
2
Solution
Determine the Electronic Configuration of Each Metal Ion:
For [V(H2O)6]3+:
Vanadium (V) has an atomic number of 23, with an electronic configuration of [Ar]3d34s2. V3+ configuration: [Ar]3d2. Number of unpaired d-electrons: 2 (even number).
For [Cr(H2O)6]2+:
Chromium (Cr) has an atomic number of 24, with an electronic configuration of [Ar]3d54s1. Cr2+ configuration: [Ar]3d4. Number of unpaired d-electrons: 4 (even number).
For [Fe(H2O)6]3+:
Iron (Fe) has an atomic number of 26, with an electronic configuration of [Ar]3d64s2. Fe3+ configuration: [Ar]3d5. Number of unpaired d-electrons: 5 (odd number).
For [Ni(H2O)6]3+:
Nickel (Ni) has an atomic number of 28, with an electronic configuration of [Ar]3d84s2. Ni3+ configuration: [Ar]3d7. Number of unpaired d-electrons: 3 (odd number).
For [Cu(H2O)6]2+:
Copper (Cu) has an atomic number of 29, with an electronic configuration of [Ar]3d104s1. Cu2+ configuration: [Ar]3d9. Number of unpaired d-electrons: 1 (odd number).
Count Complexes with Even Number of Unpaired Electrons:
From the analysis above, only [V(H2O)6]3+ and [Cr(H2O)6]2+ have an even number of unpaired d-electrons.
Conclusion:
The number of complexes with an even number of unpaired d-electrons is 2, corresponding to Option (1).