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Question

Chemistry Question on Some basic concepts of chemistry

Number of atoms of HeHe in 100u100\, u of HeHe (atomic wt of HeHe is 44) are

A

25

B

100

C

50

D

100×6×1023100\times 6\times 10^{-23}

Answer

25

Explanation

Solution

Number of atoms of a substance ==Number of gram molecular weight ×6.02×1023×\times 6.02 \times 10^{23} \times atomicity = weight of substance  number of gram molecules ×6.02×1023×=\frac{\text { weight of substance }}{\text { number of gram molecules }} \times 6.02 \times 10^{23} \times atomicity (1u=1.6×1024g\left(\because 1 u=1.6 \times 10^{-24} \,g\right. 100u=1.6×100×1024g)\left.100 \,u=1.6 \times 100 \times 10^{-24}\, g\right) =100×1.6×10244×6.023×1023×1=\frac{100 \times 1.6 \times 10^{-24}}{4} \times 6.023 \times 10^{23} \times 1 =25×1.6×1024×6.023×1023=25 \times 1.6 \times 10^{-24} \times 6.023 \times 10^{23} =25=25