Question

Number of atoms in 558.5 g of Fe (At. mass of Fe= 55.85 g $mol^{_1}$) is

• A. Twice that in $60\, g$ carbon
• B. $6.023 \times 10^{22}$
• C. Half in $8\, g$ He
• D. $558.5 \times 6.023 \times 10^{23}$

Answer 1

Answer: (A)

Twice that in $60\, g$ carbon

Answer 2

Moles of $Fe = \frac{558.5}{55.85} = 10$; Moles of $C = \frac{60}{12} = 5$