Question
Physics Question on Nuclear physics
Nucleus A is having mass number 220 and its binding energy per nucleon is 5.6 MeV. It splits in two fragments 'B' and 'C' of mass numbers 105 and 115. The binding energy of nucleons in 'B' and 'C' is 6.4 MeV per nucleon. The energy Q released per fission will be :
A
0.8 MeV
B
275 MeV
C
220 MeV
D
176 MeV
Answer
176 MeV
Explanation
Solution
220A → 105B+115C
⇒ Q = [105 × 6.4 + 115×6.4] – [220 × 5.6] MeV
⇒ Q = 176 MeV
The correct option is (D) : 176 MeV