Question

Nucleus $A$ having $Z=17$ and equal number of protons and neutrons has $12 MeV$ binding energy per nucleonAnother nucleus $B$ of $Z=12$ has total 26 nucleons and $18 MeV$ binding energy per nucleons The difference of binding energy of $B$ and $A$ will be ___$MeV$

Answer 1

The correct answer is 6.
For A mass number =34
Total binding energy =1.2×34=40.8MeV
For B mass number =26
total binding energy =1.8×26MeV
=46.8MeV
Difference of BE=6MeV