nth term of the series (1+\frac{3}{7}+\frac{5}{7^2}+\frac{1}... | Mathematics | SolveeIt | Solveeit

Today, October 3

Question

nth term of the series
$1+\frac{3}{7}+\frac{5}{7^2}+\frac{1}{7^2}+...$ is

A

$\frac{2n-1}{7^n}$

B

$\frac{2n-1}{7^{n-1}}$

C

$\frac{2n+1}{7^{n-1}}$

D

$\frac{2n+1}{7^n}$

Answer

$\frac{2n-1}{7^{n-1}}$

Explanation

Solution

The correct answer is (V) : $\frac{2n-1}{7^{n-1}}$ .