Question
Question: Norton’s theorem gives: A) An equivalent current source in parallel with an equivalent impedance ...
Norton’s theorem gives:
A) An equivalent current source in parallel with an equivalent impedance
B) An equivalent current source in series with an equivalent impedance
C) An equivalent voltage source in parallel with an equivalent impedance
D) An equivalent voltage source in series with an equivalent impedance
Solution
In the case of converting the complex circuit into the simplified circuit, we use Norton’s theorem. He proposed the concept of converting the complex circuit having numerous resistances and voltages into the simple circuit containing only the current source and the resistance. This single current source and the resistance are called as the Norton’s current and Norton’s equivalent resistance to that circuit.
Complete step by step answer:
(i) Norton’s theorem states that “any circuit has several energy sources; resistances can be replaced by an equivalent current source in parallel with the single resistance”
(ii) From this explanation, we get a direct answer option. That Norton theorem gives an equivalent circuit with an equivalent current source in parallel with equivalent impedance.
Therefore, the correct option is A.
Additional information:
(i) When the circuit is having so many voltages, divide that voltage by the resistance we find. Giving that current to the current source in Norton’s equivalent circuit and connecting Norton’s resistance in parallel to the current gives Norton’s equivalent circuit.
(ii) In similar to Norton’s theorem, there is a ‘Thevenin theorem’. Thevenin’s theorem states that the complex circuit has many voltages that can be replaced by the circuit having a voltage source in series with the resistance across the load.
(iii) We use Norton and Thevenin theorem for the simplifications of the circuit, circuit analysis, and the steady-state response.
Note:
Using Norton’s theorem, we can simplify the complex circuits having several voltages and resistances by Norton’s equivalent circuit which has the current source in parallel with an equivalent resistance. These simplified circuits are easy in the calculation and finding the efficiency of the circuit. And if there any error in the circuit can be easily rectified.