Question
Question: Normalization of 10ml of '20 V' \({H_2}{O_2}\) is: A. 1.79 B. 3.58 C. 60.86 D. 6.086...
Normalization of 10ml of '20 V' H2O2 is:
A. 1.79
B. 3.58
C. 60.86
D. 6.086
Solution
In this question using the given values determine the number of moles present and then determine the normality with the help of normality and molarity relation.
Complete answer:
Now from the question
20V H2O2 means one litre of H2O2 solution will be producing 20 litres of oxygen
It is known that,
2H2O2→2H2O+O2
Now, 2 moles of H2O2→1moleO2
20V H2O2 produces 20litre O2
or, 1 litre H2O2 produces 20 litres O2
1 litre H2O2 will produce (22.4L20L) moles of O2
Now, number of moles in 1 litre of H2O2
=2×no.ofMolesofO2
=2×22.420
=1.79moles
Now, Molarity=Volume of Solution(Litre)moles of solute
=11.79=1.79M
Now Normality is given by:
The relation between Normality and Molarity
N=n×M
where 'n' is the number of equivalents
now from the question
nforH2O2=2
therefore,
Normality N=2×1.79
Normality=3.58N
Hence the correct option is B .
Note:
RELATION BETWEEN NORMALITY AND MOLARITY :-
Normality is defined as the number of gram equivalent of solute dissolved in one litre of solution. The unit of normality is N. It is mostly used in titration calculations. The Normality of normal solutions is one.
Normality=Equivalent Mass of SoluteMolecular Mass
Molarity of a solution is defined as the number of moles of solute dissolved in one liter of the solution. The unit is M or mol L-1 . It is the most preferred unit of concentration.
Molarity=Volume of Solution(Litre)Number of moles of Solute
Molarity and Normality are related as follows:
Normality=Molarity×Equivalent MassMolar Mass
The normality of acids can be calculated with the following formula:
Normality = Molarity x Basicity
The value for basicity can be known by counting the number of H+ ions an acid molecule can give.
The normality of bases can be calculated with the following formula:
Normality = Molarity x Acidity
The value for acidity can be known by counting the number of OH− ions a base molecule can give.