Question: No. of terms in the expansion of (1 + x)101 (1 + x2 – x)100 is...

Question

No. of terms in the expansion of (1 + x)¹⁰¹ (1 + x² – x)¹⁰⁰ is

Answer 1

(1 + x) {(1 + x) (1 + x² – x)}¹⁰⁰

$\frac{= (1 + x)(1 + x^{3})^{100}}{101terms}$

Æ

two type terms = Power of x 3k type & power of x (3k + 1) type = 101 + 101 = 202 terms

Question: No. of terms in the expansion of (1 + x)<sup>101</sup> (1 + x<sup>2</sup> – x)<sup>100</sup> is...