Question

Nitrogen has no d-orbital in its valence shell and therefore it cannot1) Exhibits the oxidation state of +52) Have covalency greater than 33) Exhibit orbital Hybridization4) Form oxides with oxidation states greater than +5Select the correct answer using codes given below:

• A. (A) 1 only
• B. (B) 2 only
• C. (C) 1, 2 and 3
• D. (D) 1 and 4 only

Answer 1

Answer: (B)

(B) 2 only

Answer 2

Explanation:
Nitrogen shows covalency of 4 by coordinate bonding when it donates ns-electron pair to Lewis acid. So, statement 2 is correct.Nitrogen exhibits the oxidation state ranging from -3 in ammonia and +5 in Nitric Acid. So, statement 1 is incorrect.Since Nitrogen has no d-orbitals, it cannot undergo sp3 hybridization. So, statement 3 is incorrect.Nitrogen forms oxides within the range to +5. So, statement 4 is incorrect.Hence, the correct option is (B).