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Question

Chemistry Question on Amines

Nitrobenzene on treatment with zinc dust and aqueous ammonium chloride gives

A

C6H5N=N−C6H5C _{6} H _{5} N = N - C _{6} H _{5}

B

C6H5NH2C _{6} H _{5} NH _{2}

C

C6H5NOC _{6} H _{5} NO

D

C6H5NHOHC _{6} H _{5} NHOH

Answer

C6H5NHOHC _{6} H _{5} NHOH

Explanation

Solution

When nitrobenzene is reduced with a neutral reducing agent (Zn\left( Zn\right. dust +NH4Cl,Al−Hg+ NH _{4} Cl , Al - Hg couple and water), pheylhydroxylamine is formed. C6H5NO2 Nitrobenzene +2[H]→+NH4Cl−H2OZn dust C6H5NO Nitrosobenzene →2[H]C6H5NHOHPhenyl hydroxylamine\underset{\text { Nitrobenzene }}{ C _{6} H _{5} NO _{2}}+2[ H ] \xrightarrow [+ NH _{4} Cl - H _{2} O ]{ Zn \text { dust }} \underset{\text { Nitrosobenzene }}{ C _{6} H _{5} NO } \xrightarrow{2[ H ]} \underset {\text{Phenyl hydroxylamine}}{C _{6} H _{5} NHOH}