Question
Quantitative Aptitude Question on Algebra
Nitish booked movie tickets online which collects the same internet handling charges for normal movies and 3D movies, whereas the cost price of each normal movie ticket is 80% of the 3D movie ticket. Nitish paid Rs. 1030 for two 3D movie tickets and 3 normal tickets and Rs. 610 for one 3D movie ticket and 2 normal tickets. Find the internet handling charges per ticket.
10
30
40
50
30
Solution
Let the internet handling charges for each ticket be Rs. I and the price of each 3D movie ticket be Rs. X. So, the price of each normal movie ticket= Rs. 54 X
2 × X + 3 ×54× X + 5 × I = 1030
22 × X + 25 × I = 5150.......... (1)
Also, X + 2 ×54 × X + 3 × I = 610
13 × X + 15 × I = 3050........ (2)
Equation (1) X 3 – (2) X 5 gives:
66X + 75I − 65X − 75I = 15450 − 15250
X = 200
So, I = 30
i.e., the internet handling charges for each ticket is Rs. 30.
So, the correct option is (B) : 30.