Question

Ni CO4 cn 4 what is hybrid

• A. sp3
• B. dsp2
• C. d2sp3
• D. sp2

Answer 1

Answer: (A)

sp3

Answer 2

In the complex [Ni(CO)4], Nickel (Ni) has an oxidation state of 0 because the carbonyl ligand (CO) is neutral. The electronic configuration of Ni(0) is $[Ar] 3d^8 4s^2$. Carbonyl (CO) is a strong field ligand, which causes the pairing of electrons. The two electrons in the $4s$ orbital are pushed into the $3d$ orbitals, resulting in a filled $3d$ subshell ($3d^{10}$). The coordination number of Ni is 4. To accommodate the four CO ligands, Ni utilizes its empty $4s$ orbital and three $4p$ orbitals. These orbitals hybridize to form four equivalent $sp^3$ hybrid orbitals, leading to a tetrahedral geometry. The "cn 4" part of the question is ambiguous and does not form a standard chemical notation for a complex. Assuming the primary intent was to ask for the hybridization of Ni in [Ni(CO)4], the hybridization is $sp^3$.