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Question: NH<sub>4</sub>COONH<sub>2</sub>(s) ![](https://cdn.pureessence.tech/canvas_559.png?top_left_x=300&to...

NH4COONH2(s) 2NH3(g) + CO2(g). If equilibrium pressure is 3 atm for the above reaction; Kp will be –

A

4

B

27

C

4/27

D

1/27

Answer

4

Explanation

Solution

NH4COONH2(s) 2NH3(g) + CO2(g)

2P =2 P = 1

3P = 3 Ž P = 1

Kp = pNH32×pCO2{p_{NH}}_{3}^{2} \times p_{CO_{2}} = 22 × 1 = 4