Question

Neglecting the masses of the string and pulley and ignoring the friction in the system, we find that

• A. Weights fall freely. Pulley B rotates clockwise and pulley A, C rotate anticlockwise.
• B. The two weights have different accelerations. Pulley C rotates clockwise and B, C rotate anticlockwise.
• C. Acceleration of masses will be zero and the system will be at rest.
• D. Acceleration of masses is equal to g. Pulley A and C rotate clock wise where as B rotates anticlockwise.

Answer 1

Answer: (A)

Weights fall freely. Pulley B rotates clockwise and pulley A, C rotate anticlockwise.

Answer 2

Here m₁g – T = m₁a₁

(taking a₁ as downward acceleration of m₁)

2T – m₂g = m₂a₂

(taking a₂ as upward acceleration of m₂)

and 2T – T = 0 ( mass of pulley is zero)

Thus, T = 0 ∴ a₁ = a₂ = g

Thus, the masses will have free fall.

Clearly pulley B rotates clockwise and the other pulleys in anticlockwise direction.