Question

Nearest point on line x –3y = 5 from point (1, 2) is :

• A. (2, –1)
• B. (3, – $\frac{2}{3}$)
• C. (0, 0)
• D. (5, 0)

Answer 1

Answer: (A)

(2, –1)

Answer 2

Point must be point of intersection of given line &

perpendicular line passing through (1, 2)

i.e. 3x + y = 5

Ž (2, – 1)