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Question

Chemistry Question on Solutions

Nalorphene (C19H21NO3) (C_{19}H_{21}NO_3 ), similar to morphine, is used to combat withdrawal symptoms in narcotic users. Dose of nalorphene generally given is 1.5 mg. Calculate the mass of 1.5×103m1.5 \times 10^{–3} m aqueous solution required for the above dose.

Answer

The correct answer is: 3.22 g
The molar mass of nalorphene (C19H21NO3)(C_{19}H_{21}NO_3) is given as:
19×12+21×1+1×14+3×16=311gmol119 × 12 + 21 × 1+1 \times 14+ 3 \times 16=311\, g\, mol^{-1}
In 1.5×103m1.5 \times 10^{-3} m aqueous solution of nalorphene,
1 kg (1000 g) of water contains 1.5×103mol=1.5×103×311g1.5 \times 10^{-3} mol= 1.5 \times 10^{-3} \times 311 g
=0.4665g= 0.4665 g
Therefore, total mass of the solution =(1000+0.4665)g
= 1000.4665 g
This implies that the mass of the solution containing 0.4665 g of nalorphene is 1000.4665 g.
Therefore, mass of the solution containing 1.5 mg of nalorphene is:
(1000.4665×1.5×103)0.4665g\frac{(1000.4665 \times 1.5 \times 10^{-3})}{0.4665} g
= 3.22 g
Hence, the mass of aqueous solution required is 3.22 g.
Note: There is a slight variation in this answer and the one given in the NCERT textbook.