NaCl reacts with conc. ( H\_2SO\_4 ) and ( K\_2Cr\_2O\_7 ) t... | Chemistry | SolveeIt

Question

NaCl reacts with conc. $H_2SO_4$ and $K_2Cr_2O_7$ to give reddish fumes (B), which react with NaOH to give yellow solution (C). (B) and (C) respectively are:

$CrO_2Cl_2, Na_2CrO_4$

$Na_2CrO_4, CrO_2Cl_2$

$CrO_2Cl_2, KHSO_4$

$CrO_2Cl_2, Na_2Cr_2O_7$

Answer

$CrO_2Cl_2, Na_2CrO_4$

Explanation

Solution

The reactions involved are:
NaCl + conc. H2SO4 + K2Cr2O7 → CrO2Cl2 + KHSO4 + NaHSO4 + H2O
(B) is CrO2Cl2 (reddish fumes). On reaction with NaOH, it produces a yellow solution (C) which is Na2CrO4:
CrO2Cl2 + NaOH → Na2CrO4 + NaCl + H2O

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