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Question: \(NaBH_{4} + I_{2} \rightarrow X + Y + Z\) \[BF_{3} + NaH\overset{\quad 450K\quad}{\rightarrow}X + ...

NaBH4+I2X+Y+ZNaBH_{4} + I_{2} \rightarrow X + Y + Z

BF3+NaH450KX+PBF_{3} + NaH\overset{\quad 450K\quad}{\rightarrow}X + P

BF3+LiAlH4X+Q+RBF_{3} + LiAlH_{4} \rightarrow X + Q + R

X,Y, Z, P, Q and R in the reactions are

XYZPQR
A

| Na4B4O7{Na_{4}B_{4} }O_{7} | NaI | | HI | HF | LiF | AlF3AlF_{3} | |

B

| B2H6B_{2}H_{6} | NaI | | H2H_{2} | NaF | LiF | AlF3AlF_{3} | |

C

| B2H6B_{2}H_{6} | BH3BH_{3} | | NaI | B3N3H6{B_{3}N_{3} }H_{6} | Al2F6Al_{2}F_{6} | AlF3AlF_{3} | |

D

| BH3BH_{3} | B2H6B_{2}H_{6} | | H2H_{2} | B3N3H6{B_{3}N_{3} }H_{6} | LiF | AlF3AlF_{3} | |

Explanation

Solution

: 2NaBH4+I2B2H6(X)+2NaI(Y)+H2(Z)2NaBH_{4} + I_{2} \rightarrow \underset{(X)}{B_{2}H_{6}} + \underset{(Y)}{2NaI} + \underset{(Z)}{H_{2}}

2BF3+6NaH450KB2H6(X)+6NaF(P)2BF_{3} + 6NaH\overset{\quad 450K\quad}{\rightarrow}\underset{(X)}{B_{2}H_{6}} + \underset{(P)}{6NaF}

4BF3+3LiAlH42B2H6(X)+3LiF(Q)+3AlF3(R)4BF_{3} + 3LiAlH_{4} \rightarrow 2\underset{(X)}{B_{2}H_{6}} + \underset{(Q)}{3LiF} + \underset{(R)}{3AlF_{3}}