Question

$NaAl{{O}_{2}}$ on hydrolysis gives:
A. $NaOH$
B. $A{{l}_{2}}{{O}_{3}}$
C. Both A and B
D. None of these

Answer 1

As we know that is called sodium aluminate, which is an inorganic compound. It is basically a pure sodium aluminate, which is white crystalline solid. It is having the formula $NaAl{{O}_{2}}$, and is available as a solid or as a solution.

Complete step by step answer:
- It is found that sodium aluminate has a three-dimensional framework in which the corner links $Al{{O}_{4}}$ tetrahedral. As we know that it is having sodium cations that are mixed with aluminium oxide anions.
$NaAl{{O}_{2}}$ on hydrolysis gives $A{{l}_{2}}{{O}_{3}}$ and sodium hydroxide.
$2NaAl{{O}_{2}}+{{H}_{2}}O\to A{{l}_{2}}{{O}_{3}}+2NaOH$
- In this reaction we can see that there is formation of aluminium oxide and sodium hydroxide takes place. It is found that this is a highly exothermic reaction.
It is found that sodium aluminate has a wide range of applications. Some of them are:
- Sodium aluminate is mostly used for wastewater treatment systems. And in municipal drinking water. It is found to provide an economical source of highly reactive alumina.
- As we know that sodium aluminate as an alkali can be used where the addition of caustic soda is basically not suitable.
Hence, we can conclude that the correct option is (c), that is both $NaOH$ and are formed on hydrolysis of $NaAl{{O}_{2}}$.

Note: We should not get confused in between the terms sodium aluminate and sodium meta aluminate. As, sodium aluminate is an oxide compound, whereas sodium meta aluminate is a hydroxide compound.