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Chemistry Question on Solutions

Na2S2O3+I2⟶Na _{2} S _{2} O _{3}+ I _{2} \longrightarrow Product is

A

Na2SNa _{2} S

B

Na2SO4Na _{2} SO _{4}

C

Na2S4O6Na _{2} S _{4} O _{6}

D

S2S _{2}

Answer

Na2S4O6Na _{2} S _{4} O _{6}

Explanation

Solution

The product of sodium thiosulphate and iodine is sodium tetra thionate.
2Na2S2O3+I2⟶Na2S4O6+2NaI sodium tetrathionate 2 Na _{2} S _{2} O _{3}+ I _{2} \longrightarrow \underset{\text { sodium tetrathionate }}{ Na _{2} S _{4} O _{6}+2 NaI }