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Question

Chemistry Question on Chemical Kinetics

N2(g)+3H2(g)2NH3(g)+22kcalN _{2}(g)+3 H _{2}(g) \rightleftharpoons 2 NH _{3}(g)+22\, kcal. The activation energy for the forward reaction is 50kcal50\, kcal. What is the activation energy for the backward reaction?

A

-72 kcal

B

-28 kcal

C

+28 kcal

D

+72 kcal

Answer

+72 kcal

Explanation

Solution

N2(g)+3H2(g)2NH3(g)+22kcalN _{2}(g)+3 H _{2}(g) \rightleftharpoons 2 NH _{3}(g)+22\, kcal \because The activation energy for the forward reaction =50kcal=50\, kcal \therefore The activation energy for the backward reaction =50+22=72kcal=50+22=72\, kcal