Question

$N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}$ The equilibrium constant for the reaction is $K$, then the equilibrium constant or the equilibrium for the reaction given beloow is: $NH _{3} \rightleftharpoons \frac{1}{2} N _{2}+\frac{3}{2} H _{2}$

• A. $1/K$
• B. $1/K^2$
• C. $\sqrt{K}$
• D. $\frac {1} {\sqrt{K}}$

Answer 1

Answer: (D)

$\frac {1} {\sqrt{K}}$

Answer 2

$N _{2}+3 H _{2} \rightleftharpoons 2 NH _{3}$ $\frac{\left[ NH _{3}\right]^{2}}{\left[ N _{2}\right]\left[ H _{2}\right]^{3}}=k_{1}=k$ $NH _{3} \rightleftharpoons \frac{1}{2} N _{2}+\frac{3}{2} H _{2}$ $K _{2} =\frac{\left[ N _{2}\right]^{1 / 2}\left[ H _{2}\right]^{3 / 2}}{\left[ NH _{3}\right]}$ On squaring both sides, $k_{2}^{2}=\frac{\left[ N _{2}\right]\left[ H _{2}\right]^{3}}{\left[ NH _{3}\right]^{2}}$ $k_{2}^{2}=\frac{1}{ k _{1}}$ $\frac{1}{\sqrt{k_{1}}}=\frac{1}{\sqrt{k}}$