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Question

Quantitative Aptitude Question on Simple and Compound Both

Mr.Pinto invests one-fifth of his capital at 6%6\%,one-third at 10%10\% and the remaining at 1%1\%,each rate being simple interest per annum.Then,the minimum number of years required for the cumulative interest income from these investments to equal or exceed his initial capital is

Answer

Let's assume Mr. Pinto's initial capital is C dollars.
He invests one-fifth of his capital at 6%6\%,which means he invests (15)×C(\frac{1}{5})\times{C} dollars at 6%6\% interest per annum.The interest earned from this investment after t years is (15)×C×0.06×t(\frac{1}{5})\times{C}\times0.06\times{t}.
He also invests one-third of his capital at 10%10\%,which means he invests (13)×C(\frac{1}{3})\times{C} dollars at 10%10\% interest per annum.The interest earned from this investment after t years is (13)×C×0.10×t(\frac{1}{3})\times{C}\times0.10\times{t}.
The remaining amount,which is (11513)×C=(11/15)×C(1-\frac{1}{5}-\frac{1}{3})\times{C}=(11/15)\times{C}, is invested at 1%1\% interest per annum.The interest earned from this investment after t years is (1115)×C×0.01×t(\frac{11}{15})\times{C}\times0.01\times{t}.
Now,we want the cumulative interest income from these investments to equal or exceed his initial capital, which is C dollars.So,we can set up the following inequality:
(15)×C×0.06×t+(1/3)×C×0.10×t+(1115)×C×0.01×tC(\frac{1}{5})\times{C}\times0.06\times{t}+(1/3)\times{C}\times0.10\times{t}+(\frac{11}{15})\times{C}\times0.01\times{t≥C}
Now,let's solve for t:
(15)×0.06×t+(13)×0.10×t+(1115)×0.01×t1(\frac{1}{5})\times0.06\times{t}+(\frac{1}{3})\times0.10\times{t}+(\frac{11}{15})\times0.01\times{t≥1}
Simplify:
0.012t+0.0333t+0.0073t ≥ 1
Combine the terms:
0.0523t ≥ 1
Now, divide both sides by 0.0523:
t10.0523t ≥ \frac{1}{0.0523}
t ≥ 19.13
Since the time (t) must be a whole number of years, the minimum number of years required for the cumulative interest income from these
investments to equal or exceed his initial capital is 20 years.