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Physics Question on Nuclei

MP denotes the mass of a proton and Mn that of a neutron. A given nucleus, of binding energy B, contains Z protons and N neutrons. The mass M(N, Z) of the nucleus is given by (c is the velocity of light )

A

M(N, Z) = NMn + ZMP + Bc2

B

M(N, Z) = NMn + ZMP – Bc2\frac{B}{c^2}

C

M(N, Z) = NMn + ZMP +Bc2\frac{B}{c^2}

D

M(N, Z) = NMn + ZMP – Bc2

Answer

M(N, Z) = NMn + ZMP – Bc2\frac{B}{c^2}

Explanation

Solution

The mass M(N, Z) of a nucleus with Z protons and N neutrons is given by M(N, Z) = NMn + ZMP – Bc2\frac{B}{c^2}.
Therefore, the correct option is (B) : M(N, Z) = NMn + ZMP – Bc2\frac{B}{c^2}