Question

Motion of a particle is given by equation $S=(3t^3+7t^2+14t+8)\ m$, The value of acceleration of the particle at $t=1 \ sec$ is:

• A. $10\ m/s^2$
• B. $32 \ m/s^2$
• C. $23\ m/s^2$
• D. $16\ m/s$

Answer 1

Answer: (B)

$32 \ m/s^2$

Answer 2

$v =\frac {ds}{dt}$

$v = \frac {d}{dt} (3t^3+7t^2+14t+8)$

$v =9t^2+14t+14$

$a=\frac {dv}{dt}$

$a =$ $\frac {d}{dt}( 9t^2+14t+14)$

$a =18t+14$

$at,\ t=1\ sec$

$a=32\ ms^{-2}$

So, the correct option is (B): $32 \ m/s^2$