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Question

Physics Question on Uniform Circular Motion

Motion of a particle in xy plane is described by a set of following
x=4sin(π2ωt)mx = 4sin (\frac{π}{2} - ωt )m
and y = 4sin(ω t) m. The path of the particle will be

A

Circular

B

Helical

C

Parabolic

D

Elliptical

Answer

Circular

Explanation

Solution

The correct answer is (A) : Circular
x=4sin(π2ωt)x = 4sin (\frac{π}{2} - ωt )
=4cos(ωt)= 4cos(ωt)
y=4sin(ωt)y = 4 sin(ωt)
x2+y2=42⇒ x^2 + y^2 = 4^2
⇒ The particle is moving in a circular motion with radius of 4 m.