Question
Physics Question on Uniform Circular Motion
Motion of a particle in x – y plane is described by a set of following
x=4sin(2π−ωt)m
and y = 4sin(ω t) m. The path of the particle will be
A
Circular
B
Helical
C
Parabolic
D
Elliptical
Answer
Circular
Explanation
Solution
The correct answer is (A) : Circular
x=4sin(2π−ωt)
=4cos(ωt)
y=4sin(ωt)
⇒x2+y2=42
⇒ The particle is moving in a circular motion with radius of 4 m.