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Question

Physics Question on Photoelectric Effect

Monochromatic radiation emitted when electron on hydrogen atom jumps from first excited to the ground state irradiates a photosensitive material. The stopping potential is measured to be 3.57V.3.57\, V. The threshold frequency of the material is

A

4×1015Hz4 \times 10^{15} Hz

B

5×1015Hz5 \times 10^{15} Hz

C

1.6×1015Hz1.6 \times 10^{15} Hz

D

2.5×1015Hz2.5 \times 10^{15} Hz

Answer

1.6×1015Hz1.6 \times 10^{15} Hz

Explanation

Solution

Energy released from emmition of electron is E=(3.4)(13.6)=10.2eVE =(-3.4)-(-13.6)=10.2\, eV. From photo-electric equation, work function ϕ=EeV0=hv0\phi= E - eV _{0}= h v _{0} On Solving this v0=1.6×1015Hzv_{0}=1.6 \times 10^{15}\, Hz