Question
Physics Question on Moment Of Inertia
Moment of inertia of ring about its diameter is I Then, moment of inertia about an axis passing through centre perpendicular to its plane is
A
2I
B
2I
C
23I
D
I
Answer
2I
Explanation
Solution
By the theorem of perpendicular axes, the moment of inertia about the central axis IC , will be equal to the sum of its moments of inertia about two mutually perpendicular diameters lying in its plane.
Thus, Id=I=21MR2
∴IC=I+I
=21MR2+21MR2
=I+I=2I