Question

Moment of inertia of a thin circular plate of mass M, radius R about an axis passing through its diameter is I. The moment of inertia of circular ring of mass M, radius R about an axis perpendicular to its plane and passing through its center is

• A. 2 I
• B. $\frac{I}{2}$
• C. 4 I
• D. $\frac{I}{4}$

Answer 1

Answer: (C)

4 I

Answer 2

$I = \frac{MR^2}{4}$ ; $I' =MR^2$