Moment of inertia of a ring of mass (M) and radius (R) about... | Physics | SolveeIt | Solveeit

Today, August 18

Question

Moment of inertia of a ring of mass $M$ and radius $R$ about a tangent to the circle of the ring is

A

$\frac{5}{2}M{{R}^{2}}$

B

$\frac{3}{2}M{{R}^{2}}$

C

$\frac{1}{2}M{{R}^{2}}$

D

$M{{R}^{2}}$

Answer

$\frac{3}{2}M{{R}^{2}}$

Explanation

Solution

Moment of inertia of a ring about a tangent ${{I}_{t}}=\frac{M{{R}^{2}}}{2}+M{{R}^{2}}$ $=\frac{3}{2}M{{R}^{2}}$