Question

Moment of inertia of a disc of mass $M$ and radius ' $R$ ' about any of its diameter is $\frac{M^2}{4}$ The moment of inertia of this disc about an axis normal to the disc and passing through a point on its edge will be, $\frac{x}{2} MR ^2$ The value of $x$ is __

Answer 1

The correct answer is 3.

I=Icm​+Md2
=2MR2​+MR2
=23​MR2
x=3