Solveeit Logo

Question

Question: Molecules of an ideal gas are known to have three translational degrees of freedom. The gas is maint...

Molecules of an ideal gas are known to have three translational degrees of freedom. The gas is maintained at a temperature of T. The total internal energy, U of a mole of this gas, and the value of γ=(CpCv)\gamma = (\frac{C_p}{C_v}) are given respectively, by

A

U=52RT\frac{U}{}=\frac{5}{2}RT and γ=65\gamma = \frac{6}{5}

B

URT=5\frac{U}{RT}=5 and γ=75\gamma = \frac{7}{5}

C

U=52RT\frac{U}{}=\frac{5}{2}RT and γ=75\gamma = \frac{7}{5}

D

U=5RTU = 5RT and γ=65\gamma = \frac{6}{5}

Answer

U=52RT\frac{U}{}=\frac{5}{2}RT and γ=75\gamma = \frac{7}{5}

Explanation

Solution

Assuming the ideal gas is diatomic (as implied by the options), it has f=5f=5 degrees of freedom (3 translational + 2 rotational).

Internal energy per mole U=f2RT=52RTU = \frac{f}{2}RT = \frac{5}{2}RT.

Molar specific heat at constant volume Cv=f2R=52RC_v = \frac{f}{2}R = \frac{5}{2}R.

Molar specific heat at constant pressure Cp=Cv+R=52R+R=72RC_p = C_v + R = \frac{5}{2}R + R = \frac{7}{2}R.

Ratio of specific heats γ=CpCv=7/2R5/2R=75\gamma = \frac{C_p}{C_v} = \frac{7/2 R}{5/2 R} = \frac{7}{5}.