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Question

Chemistry Question on The Valence Shell Electron Pair Repulsion (VSEPR) Theory

Molecule having least dipole moment is:

A

(CH3)2CH2\left( CH _{3}\right)_{2} CH _{2}

B

CH2=CHCCHCH _{2}= CH - C \equiv CH

C

CH3CH2CCHCH _{3} CH _{2} C \equiv CH

D

H3CCCCH3H _{3} C \cdot C \equiv C - CH _{3}

Answer

H3CCCCH3H _{3} C \cdot C \equiv C - CH _{3}

Explanation

Solution

H3CCCCH3H _{3} C \cdot C \equiv C \cdot CH _{3} has zero dipole inoment due to symmetrical structure with linear geometry. Hence, its dipole moment is the least among these.