Question
Question: Molecular weight of \({\text{KBr}}{{\text{O}}_{\text{3}}}\) is \({\text{M}}\). What is its equivalen...
Molecular weight of KBrO3 is M. What is its equivalent weight, if the reaction is:
BrO3−→Br− (acidic medium)
(A) M
(B) 4M
(C) 6M
(D) 6M
Solution
The valency factor for acids is the basicity i.e. the number of hydrogen ions released by an acid. The valency factor for bases is the acidity i.e. the number of hydroxide ions released by a base. Valency factor in a redox reaction is equal to the number of moles of electrons lost or gained per molecule.
Formula used: Equivalent weight =Xmolecular weight
Where X is the valency factor.
Complete answer: The given compound KBrO3 refers to a potassium salt and bromate salt. The molecular weight of KBrO3 is M. Calculate the oxidation state of bromine in BrO3−. This can be done by assuming the oxidation state of bromine as x. We know that the oxidation state of oxygen is −2. In a polyatomic ion, the sum of the oxidation numbers of all the atoms present in it is equal to the total charge on the ion.
So, we can write it as x+3(−2)=−1
x−6=−1
x=5
So, the oxidation state of bromine in BrO3− is +5
The change in oxidation state in the reaction BrO3−→Br− is 5−(−1)=6
⇒ Equivalentweight=Xmolecular weight
Equivalentweight=6M
Therefore, option C is the correct answer.
Note:
The equivalent weight is the weight of a substance that contains a single reactive proton (or single hydrogen ion) or a single reactive hydroxide ion. Equivalent weight is the weight of a substance which has a single reactive proton in the case of acids which are proton donors and it is the weight of a substance which has a single reactive hydroxide ion in the case of bases which are proton acceptors.