Solveeit Logo
Login

Question

Question: Molecular mass of a gas is 78. Its density at \(98^{0}C\)and 1 atm will be...

Molecular mass of a gas is 78. Its density at 980C98^{0}Cand 1 atm will be

A

200gL−1‘200gL^{- 1`}

B

2.56gL−12.56gL^{- 1}

C

256gL−1256gL^{- 1}

D

78gL−178gL^{- 1}

Answer

2.56gL−12.56gL^{- 1}

Explanation

Solution

: P = atm, T=980CT = 98^{0}C +273=273 K, M = 78gmol−178gmol^{- 1}

R=0.0821Latmk−1mol−1R = 0.0821Latmk^{- 1}mol^{- 1}

PM=dRTord=PMRT=1×780.0821×371=2.56gL−1PM = dRTord = \frac{PM}{RT} = \frac{1 \times 78}{0.0821 \times 371} = 2.56gL^{- 1}