Question
Chemistry Question on Mole concept and Molar Masses
Mole fraction of a solute in benzene is 0.2 then find molality of solute:
A
3.2
B
2
C
4
D
3.6
Answer
3.2
Explanation
Solution
Let the solution be x molal then moles of solute present in 1000g of benzene =781000=12.82 moles. ∴ Mole fraction of solute =x+12.82x 0.2=x+12.82x 0.2(x+12.82)=x 0.2x+2.564=x 2.564=x−0.2x =0.8x x=0.82.564=3.2