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Question

Chemistry Question on Mole concept and Molar Masses

Mole fraction of a solute in benzene is 0.20.2 then find molality of solute:

A

3.2

B

2

C

4

D

3.6

Answer

3.2

Explanation

Solution

Let the solution be xx molal then moles of solute present in 1000g1000\, g of benzene =100078=12.82=\frac{1000}{78}=12.82 moles. \therefore Mole fraction of solute =xx+12.82=\frac{x}{x+12.82} 0.2=xx+12.820.2=\frac{x}{x+12.82} 0.2(x+12.82)=x0.2(x+12.82) =x 0.2x+2.564=x0.2 x+2.564 =x 2.564=x0.2x2.564 =x-0.2 x =0.8x=0.8 x x=2.5640.8=3.2x=\frac{2.564}{0.8}=3.2