Question

Molarity of ${0.2\, N \,H_2SO_4}$ is

• A. 0.2 M
• B. 0.4 M
• C. 0.6 M
• D. 0.1 M

Answer 1

Answer: (D)

0.1 M

Answer 2

{ Molarity = \frac{ Normality}}{n} = \frac{0.2}{2} = {0.1 \, M}
$\bigg[ \because \, n = { \frac{Mol. mass}{E mass} = \frac{98}{49} = 2}\bigg]$