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Question

Chemistry Question on Electrochemistry

molar ionic conductivities of a divalent cation and anion are 57S cm2mol157 \, \text{S cm}^2 \text{mol}^{-1} and 73S cm2mol173 \, \text{S cm}^2 \text{mol}^{-1}, respectively. The molar conductivity of the solution of an electrolyte with the above cation and anion will be:

A

65S cm2mol165 \, \text{S cm}^2 \text{mol}^{-1}

B

130S cm2mol1130 \, \text{S cm}^2 \text{mol}^{-1}

C

187S cm2mol1187 \, \text{S cm}^2 \text{mol}^{-1}

D

260S cm2mol1260 \, \text{S cm}^2 \text{mol}^{-1}

Answer

130S cm2mol1130 \, \text{S cm}^2 \text{mol}^{-1}

Explanation

Solution

The molar conductivity of a solution (ΛSolution) is given by the sum of molar ionic conductivities:

Λ+2C = 57 S cm2 mol-1
Λ+2A = 73 S cm2 mol-1

ΛSolution = λ+ + λ-
ΛSolution = 57 + 73 = 130 S cm2 mol-1