Question

Molar concentration of $O_{2}$ is 96 gm, it contained in 2 litre vessel, active mass will be

• A. 16 mole/litre
• B. 1.5 mole/litre
• C. 4 mole/litre
• D. 24 mole/litre

Answer 1

Answer: (B)

1.5 mole/litre

Answer 2

Active mass

$= \frac{\frac{\text{weight}}{\text{M.wt.}}}{\text{Volume}} = \frac{\text{weight}}{\text{M.wt.} \times \text{Volume}} = \frac{96}{32 \times 2} = \frac{3}{2} = 1.5mol/litre$