Question
Question: \(MnO_4^{2 - }\) changes to \(Mn{O_2}\) into \(MnO_4^ - \) in acidic medium. Calculate equivalent we...
MnO42− changes to MnO2 into MnO4− in acidic medium. Calculate equivalent weight of MnO42−.
A) 1M
B) 21M
C) 23M
D) 3M
Solution
At first we will write what is given in the question. Then we will write what MnO42− is. Then we will write the reaction of MnO42− with water. We will know what is the type of the reaction. Then we will find the equivalent weight of MnO42− . We will also find where reduction and oxidation reactions happen.
Complete solution:
Step1. We are given with MnO42−. It will be disproportionate to MnO2 and MnO4−. We need to calculate the equivalent weight of MnO42−.
Step2. MnO42− is called manganite . Its molecular weight is 118.936 g/mol. It is an inorganic compound which is a divalent anion formed by removal of both the protons from manganic acid.
Step3. The MnO42− breaks into two different compounds. While it water it breaks and releases hydrogen ions. It is the disproportionation reaction. In the disproportionation reaction the equivalent weight of the species undergoing the disproportionation. While disproportionation one will be oxidizing asn another is reducing it can also be called redox reaction.
Step4. MnO42− → MnO2
The oxidation number of Mn in MnO42− is six and the oxidation number of MnO2is four. It is reducing. The difference is two then the molecular weight is mol.wt/2.
MnO42− → MnO4−
The oxidation number of Mn in MnO42−is six and the oxidation number of MnO4− is seven so the equivalent weight is 1mol.wt .
So total equivalent weight is 2M+1M=23M
Hence the correct answer is 23M.
Note: To solve such questions, we must know what redox reactions are and how they work, A redox reaction can be defined as a chemical reaction in which electrons are transferred between two reactants participating in it. The oxidation reaction can be identified as the oxidation state changes.