Question

$[ML^{3}T^{-3}A^{-2}]$ is the dimensional formula of

• A. resistance
• B. resistivity
• C. conductance
• D. conductivity

Answer 1

Answer: (B)

resistivity

Answer 2

Resistances $=\frac{\text{Potential difference}}{\text{Current}}$ $=\frac{\left[ML^{2}T^{-3}A^{-1}\right]}{\left[A\right]}=\left[ML^{2}T^{-3}A^{-2}\right]$ Resistivity =\frac{\text{Resistance \times Area}}{\text{Length}} $=\frac{\left[ML^{2}T^{-3}A^{-2}\left[L^{2}\right]\right]}{\left[L\right]}=\left[ML^{3}T^{-3}A^{-2}\right]$ Conductance $=\frac{1}{\text{Resistivity}}=\left[M^{-1}L^{-3}T^{3}A^{2}\right]$ $\therefore \left[ML^{3}T^{-3}A^{-2}\right]$ is the dimensional formula of resistivity.