Question

Mixture X= 0.02 mole of $[Co(NH_3)_5SO_4]Br$ and 0.02 mole of $[Co(NH_3)_5Br]SO_4$ was prepared in 2 L of solution. 1 L of mixture X + excess $AgNO_3 \rightarrow Y$ 1 L of mixture X + excess $BaCI_2 \rightarrow Z$ Number of moles of Y and Z are

• A. 0.01, 0.01
• B. 0.02, 0.01
• C. 0.01, 0.02
• D. 0.02, 0.02

Answer 1

Answer: (A)

0.01, 0.01

Answer 2

In 1 L solution, there will be 0.01 mole of each $[Co(NH_3)_5SO_4]$ Br and $[Co(NH_3)_5Br]SO_4.$ Addition of excess of $AgNO_3$ will give 0.01 mole of AgBr. Addition of excess of $BaCI_2$ will give 0.01 mole of $BaSO_4.$