Question

Mixture X = 0.02 mol of $[Co{(N{H_3})_5}S{O_4}]Br$ and 0.02 mol of $[Co{(N{H_3})_5}Br]S{O_4}$ was prepared in 2L of solution.
1 L of mixture X + excess$AgN{O_3} \to Y$
1 L of mixture X + excess $BaC{l_2} \to Z$
The number of moles of Y and Z are:
A. 0.03, 0.02
B. 0.01, 0.02
C. 0.01, 001
D. 0.02, 0.02

Answer 1

A coordination compound is a compound where the central metal atom is linked with several ions or neutral molecules by coordinate bonds. This type of compound is made up of the coordination sphere which is non-ionisable and the ionization sphere which is ionisable.

Complete step by step answer:
The given question gives the mixture contains $[Co{(N{H_3})_5}S{O_4}]Br$ and $[Co{(N{H_3})_5}Br]S{O_4}$.
The volume of the solution is given as 2L
So, the concentration of the mixture can be calculated in the form of molarity as
Molarity of the solution can be represented in terms of the volume of the solution rather than the mass of the solvent as in the case of molality. It can be represented as
${{Molarity (M) = }}\dfrac{{{{Moles\; of \;solute}}}}{{{{Volume\; of \;solution in litre}}}}$
By putting the data given in the question in the above relation we get
$[[Co{(N{H_3})_5}S{O_4}]Br] = \dfrac{{002}}{{2L}} = 0.01M$
In the same manner, we can calculate the molarity of $[Co{(N{H_3})_5}Br]S{O_4}$ by the substitution of the above-given data. So, the molarity is
$[[Co{(N{H_3})_5}Br]S{O_4}] = \dfrac{{002}}{{2L}} = 0.01M$
So further calculating the moles of the product of the reaction that is Y we have to write the balanced reaction of the mixture X with the excess of $AgN{O_3}$
From the reaction with the compounds we have
$[Co{(N{H_3})_5}S{O_4}]Br + AgN{O_3} \to [Co{(N{H_3})_5}S{O_4}]N{O_3} + AgBr \downarrow$
From the reaction, we can say that the molar ratio of $[Co{(N{H_3})_5}S{O_4}]Br$ and $AgBr$ is 1:1
So the moles of Y = Moles of $AgBr$ = 0.01 mol
Similarly, the moles of Z can be calculated from the reaction as
$[Co{(N{H_3})_5}Br]S{O_4} + BaC{l_2} \to [Co{(N{H_3})_5}Br]C{l_2} + BaS{O_4} \downarrow$
From the above reaction we can see that the moles of $BaS{O_4}$ = 0.01 mol

So, the correct answer is Option C.

Note: Chemical reactions represent the chemical changes that happen in various elements. The chemical reaction is written to represent the way and proportions that the elements and compounds adopt for the formation of products.
These chemical reactions need to be balanced for the correct representation of proportions in which they react. Different proportions of the reactants provide different reactions and thus different products.